x^2+4.65x+0.45=0

Solution for x^2+4.65x+0.45=0 equation:

x^2+4.65x+0.45=0

a = 1; b = 4.65; c = +0.45;
Δ = b2-4ac
Δ = 4.652-4·1·0.45
Δ = 19.8225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4.65)-\sqrt{19.8225}}{2*1}=\frac{-4.65-\sqrt{19.8225}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4.65)+\sqrt{19.8225}}{2*1}=\frac{-4.65+\sqrt{19.8225}}{2}
$